Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
7/4 = (4 + 3)/4 = 4/4 + 3/4 = 1 + 3/4 =
1 3/4

Answer:
f(x)=3^x plot = see attachment
Step-by-step explanation:
Answer:
X = 2
Step-by-step explanation:
Divided 26 (total perimeter) by 4 = maximum side length possible = 26÷4 =.6.5
I used the trial and error technique
Guessed it was 2 working out to see if i was right or wrong:
Length: 2(2) + 3 = 4+3 = 7
Width: 3(2) = 6
7+7+6+6 = 26
Therefore X = 2
Answer:
Step-by-step explanation:
The tangent is perpendicular to the radius. The given triangle is right if AB is tangent.
Use Pythagorean to verify
- 20² = 16² + 12²
- 400 = 256 + 144
- 400 = 400
Confirmed