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ioda
3 years ago
15

Your car's back window is in the shape of a trapezoid with the dimensions shown. The 1616-inch window wiper cleans a part of the

window in a semicircular pattern. What is the approximate area of the window that is NOT cleaned by the wiper?
Mathematics
2 answers:
ExtremeBDS [4]3 years ago
5 0
<span>Semicircle area = circle area / 2 = (pi*r^2)/2 16 in is the radius. Let's call the area of this semicircle s. 3.14*16^2=s

</span><span>Trapezoid area = ((base 1 + base 2) / 2) * h Here, base 1 is 44 and base 2 is 36. The height (h) is 20. Let's call this trapezoid's area t. (44+36)/2 *20 = t
</span>
<span>We can remove the area of the semicircle (that created by the windshield wiper) by subtracting it from the area of the trapezoid. t - s = uncleaned area [(44+36)/2 * 20] - [3.14 * 16^2] = uncleaned area</span>
eduard3 years ago
5 0

Answer:

about 338

square inches

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What is the value of x, the acid concentration of the first solution?
bezimeni [28]

Answer:

A) 0.05

Step-by-step explanation:

Let's summarize into an equation the information we can get from that table.

We have 4 liters of an acid of an unknown concentration, let's call it (4x).

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And we have a total of 14 liters overall with a concentration of 0.3o.

That's like a weighted average formula: 4x + 10 y = 14z  

Let's replace the concentration values we know and solve this:

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borishaifa [10]
Step 1 : Simplify both sides
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3 years ago
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Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

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