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gayaneshka [121]
3 years ago
8

SOMEONE PLEASE HELP ME WITH THESE 3 MATH QUESTIONS!!!!!

Mathematics
1 answer:
Len [333]3 years ago
7 0

Look at the pictures (examples)

m∠1 = m∠6 → answer: none

m∠2 = m∠3 → answer: none

m∠2 = m∠C → answer: none



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Darina [25.2K]

A) The dimensions are (x+10) by (x+10).

B) The perimeter is given by 4x+40.

C) The perimeter when x is 4 is 56.

The quadratic can be factored by finding factors of c, the constant, that sum to b, the coefficient of x.  Our c is 100 and our b is 20; we want factors of 100 that sum to 20.  10*10=100 and 10+10=20, so those are what we need.  This gives us (x+10)(x+10 for the factored form.  

Since the dimensions are all (x+10), and there are 4 sides, the perimeter is given by 4(x+10).  Using the distributive property we have 4*x+4*10=4x+40.

To find the perimeter when x=4, substitute 4 into our perimeter expression:

4*4+40=16+40=56.

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Answer:

  12 1/2 laps

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To find the number of laps, divide the distance by the distance per lap.

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Answer:

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