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dalvyx [7]
3 years ago
13

Will give Brainliest. Can someone PLEASE Help Me!? I'm really confused and don't get half of this stuff and really need some hel

p.
How would you correct the proof in Question 2?

Rewrite the proof as a two-column proof, write your statements and reasons with S#) and R#) like so:

S1) Statement R1) Reason
S2) Statement R2) Reason
S3) Statement R3) Reason

(see column proof below)


Statements Reasons
1 (9+2i)(3−5i)−(9+i)(3−5i)(9+2i)(3−5i)−(9+i)(3−5i) Given
2 (3−5i)(9+2i−9+i)(3−5i)(9+2i−9+i) Factor out (3−5i)(3−5i).
3 (3−5i)(9−9+2i+i)(3−5i)(9−9+2i+i) Commutative Property of Addition
4 (3−5i)(3i)(3−5i)(3i) Combine like terms.
5 3(3i)−5i(3i)3(3i)−5i(3i) Distributive Property
6 9i−15i29i−15i2 Simplify.
7 9i−15(−1)9i−15(−1) Substitution (i2=−1)(i2=−1).
8 9i+159i+15 Simplify.
9 15+9i15+9i Commutative Property of Addition
Mathematics
1 answer:
galina1969 [7]3 years ago
4 0

Can you provide a photo

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Answer:

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vampirchik [111]

Problem 1)

The notation you wrote down is a bit odd. There seems to be a typo. Please double check.

Assuming you meant to write

a_{n} = 3 a_{n-1}

then the answer is choice D) 2, 6, 18, 54, 162, ...

-------

Why is this? Because each term is found by multiplying the previous term by 3

first term = 2

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third term = (second term)*3 = 6*3 = 18

fourth term = (third term)*3 = 18*3 = 54

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Extra information: The closed form equation is a_{n} = 2(3)^{n-1} where 2 is the first term, 3 is the common ratio, and n is a positive integer.

some more info: notice picking any term in sequence {2,6,18,54,162,...} and dividing it over its previous term leads to 3

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18/6 = 3

54/18 = 3

162/54 = 3

None of the other sequences listed have this property of the adjacent terms dividing to a constant ratio. So none of the other sequences are geometric.

================================================

Problem 2)

The first term is t_{1} = 2 (ie, the first term is 2)

The recursive definition is t_{n+1} = 3^{t_{n}} basically telling us "to get the next term, raise the prior term as an exponent with 3 as the base"

The general template looking like this: nth term = 3^(term just before the nth term)

The first term is 2, so the next term must be 3^2 = 9

The third term would be 3^9 = 19683 and so on.

-----------

<h3>Final Answer: choice B) 9</h3>
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