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2 years ago

8x plus 8y equals 8. 8x plus 2y equals 28. Find x and y

Mathematics

2 answers:

alukav5142 [94]2 years ago

6 0

Answer:

x,y = 13/3, -10/3

Step-by-step explanation:

8x+8y=8

8x+2y=28 Subtract eq1 by eq 2

6y=-20

y=-20/6 y = -10/3

8x - 80/3=8

8x=34 2/3

x=4 1/3

x=13/3

Hope this helps plz hit the crown :D

Alchen [17]2 years ago

3 0

Answer:

x = 13/3 y = 10/3

Step-by-step explanation:

8x+8y = 8

8x + 2y = 28

y = 14 - 4x make y = 1 by dividing all by 2

8x + 8 ( 14- 4x ) = 8 substitute

8x + 112 - 32x = 8

-24x = -104

x = 13/3

y = -10/3

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Maddison wants to buy a guitar she starts saving $35 each month witch equation represents maddisons savings (s) after n months

Verizon [17]

Answer:

s=$35n

Step-by-step explanation:

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3 years ago

In Death Valley, California, the highest ground temperature recorded was 94°C on July 15, 1972. In the formula C= 5/9 (F - 32) ,

gulaghasi [49]

Answer:

$F=201.2\°$

Step-by-step explanation:

we know that

$\°C=\frac{5}{9}[\°F-32]$

For $C=94\°$

substitute in the formula and solve for F

$94=\frac{5}{9}[F-32]$

$(\frac{9}{5})*94=[F-32]$

$F=(\frac{9}{5})*94+32$

$F=201.2\°$

8 0

3 years ago

The area of a circle is less than 1 dm². Find the radius of the circle. The area of a circle is less than 1 dm². Find the rad

Ipatiy [6.2K]

$\bf \textit{area of a circle}\\\\
A=\pi r^2\qquad 
\begin{cases}
\textit{let's say the Area is 1 exactly}\\
A=1
\end{cases}\implies 1=\pi r^2
\\\\\\
\cfrac{1}{\sqrt{\pi }}=r$

if you drop the radius to less than that, then the Area will also drop to less than 1 unit, in this case it happens to be a decimeter

5 0

3 years ago

What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0

2 years ago

On a piece of paper, use a protractor and a ruler to construct △ABC with AB=6 cm , m∠A=80° , and m∠B=50° .

Svetllana [295]

The correct answer for this question is this one:

<span>On a piece of paper, use a protractor and a ruler to construct △ABC with AB=6 cm , m∠A=80° , and m∠B=50° .

What is AC ?

3 cm
<u>6 cm</u>
9 cm
12 cm</span>

If you try to draw the triangle, it forms an isosceles triangle.
side AB has a length of 6cm. Side AB = Side AC. So the length of Side AC is also 6 cm.

Hope this helps answer your question and have a nice day ahead.

6 0

2 years ago

Read 2 more answers