Answer:
11
Step-by-step explanation:
just do it
Answer:
The answer to this question is 19.
Step-by-step explanation:
Given that :
f(x)=13.
f'(x)=3. 1 ≤ x ≤ 3.
Integrate
∫f'(x) dx=∫3 dx
f(x)=3x+c 1 ≤ x ≤ 3.
f(1)= 3+c
c=13-3 =10.
f(x)=3x+10 1 ≤ x ≤ 3.
now ,
f(3)=3(3)+10=19.
So f(3) is at least 19.
Answer:b=7
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2(3b−1)=40
(2)(3b)+(2)(−1)=40(Distribute)
6b+−2=40
6b−2=40
Step 2: Add 2 to both sides.
6b−2+2=40+2
6b=42
Step 3: Divide both sides by 6.
6b/6=42/6
b=7
Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
x=10
Step-by-step explanation:
We can use the Pythagorean theorem to find x
The height meets the base at a right angle
The base is bisected ( cut in half) so the base is 6 the height is 8
a^2 + b^2 = c^2
6^2 + 8^2 = x^2
36+64 = x^2
100 = x^2
Taking the square root of each side
sqrt(100) = sqrt(x^2)
10 = x
