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Ivanshal [37]
3 years ago
9

Suppose the top surface of a balance beam is 16 feet 5 inches long and 3.9 inches wide. Find the area of the top surface of the

balance beam. Choose the closest answer.
A 768.30 square inches
B 748.80 square inches
C 5.34 square inches
D 64.35 square inches
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

Option A would be your answer

Step-by-step explanation:

Had this question on Achieve3000

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The slope of the line is
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ANSWER:

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .

HOPE THIS HELP

3 0
3 years ago
2(x-3) = (x-1) + 7<br><br> Please show your steps!!
andre [41]
Simplify the equation.

First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7

Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7

Now simplify the right side of the equation by subtracting the 1 from the 7.
Resulting in: x + 6

Our goal is to isolate the x to the left side, and the numerals to the right side.
With that in mind, add the 6 (from the right side) to both sides. This cancels out the 6 on the right side.
Resulting in: 2x = 12

Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
Resulting in: x = 6

Hope this helps.
6 0
3 years ago
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The width of a rectangle, in feet, is represented by (3x-1). The length of the rectangle, in feet, is represented by (1.5x+3). F
bogdanovich [222]
Answer: 4.5x + 2

Explanation:

Sum of length and width = (3x-1)+(1.5x+3)
= 3x - 1 + 1.5x + 3
= 4.5x + 2
7 0
3 years ago
The radius of a circle is 4.9 in. Find the circumference<br> to the nearest tenth.
Archy [21]

Answer:

C = 30.8

Step-by-step explanation:

Circumference of a Circle:

C = 2πr

C = 2(3.14)(4.9)

C = 30.772

C = 30.8

5 0
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The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}&#10;\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&#10;\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&#10;y&=&{{ k}}&\cdot&x&#10;&&  y={{ k }}x&#10;\end{array}\\ \quad \\&#10;

and also

\bf \begin{array}{llllll}&#10;\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\&#10;\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\&#10;y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}&#10;&&y=\cfrac{{{  k}}}{x}&#10;\end{array}&#10;

now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad &#10;\begin{cases}&#10;V=42\\&#10;T=84\\&#10;P=8&#10;\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k&#10;\\\\\\&#10;V=\cfrac{4T}{P}\qquad now\quad &#10;\begin{cases}&#10;V=74\\&#10;P=10&#10;\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
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