$12x+3=15x\ \ \ \ |subtract\ 3\ from\ both\ sides\\\\12x=15x-3\ \ \ \ \ |subtract\ 15x\ from\ both\ sides\\\\-3x=-3\ \ \ \ \ |divide\ both\ sides\ by\ (-3)\\\\\boxed{x=1}\\\\check:\\\\L=12\cdot1+3=12+3=15\\R=15\cdot1=15\\\\L=R\ :)$

4 0

3 years ago

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How can this quadrilateral be classified? Select from the drop-down menus to complete the statements. This quadrilateral has Cho

Ilia_Sergeevich [38]

Yes, it can since it is parallel.

7 0

3 years ago

Can anyone help me solve this?

Alecsey [184]

Answer:

Step-by-step explanation:

$(\sqrt{z} +\sqrt{22})(\sqrt{z} -\sqrt{22})=35$

Subtract both sides from 35

$(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35$

Simplify:

$(\sqrt{z})^{2} -57=0$

Factor $(\sqrt{z})^{2} -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})$ =0

$\sqrt{z} +\sqrt{57}=0 or \sqrt{z} -\sqrt{57}=0$

$\sqrt{z} +\sqrt{57} =0: No Solution for Z$

$\sqrt{z} -\sqrt{57} =0: z=57$

Your answer will be z=57

and No solution

8 0

2 years ago

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TONTE UI E doove

vagabundo [1.1K]

pretty sure its growth

5 0

2 years ago

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