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I am Lyosha [343]
3 years ago
9

the entry fee at a small fair is $1.50 for children and $4.00 for adults . on a certain day 1900 people enter the fair and $4402

.50 is collected how many children went to the fair?
Mathematics
1 answer:
umka21 [38]3 years ago
7 0

150x + 400(1900-x) = 440250

150x + 760000 - 400x = 440250

250x = 319750

x = 1279

There were 1,279 children.

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MakcuM [25]

Answer:

B) A/l

Step-by-step explanation:

Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other.

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A = l * w

(A)/l = (l)/l * w

w = A/l

B) A/l is your answer.

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7 0
3 years ago
Read 2 more answers
x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −
snow_tiger [21]
For this case, what we must do is fill squares in all the expressions until we find the correct result.
 We have then:
 
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 x2  − 4x + y2 + 12y = 20
 x2  − 4x + (12/2)^2 + y2 + 12y  + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
 x2  − 4x + (6)^2 + y2 + 12y  + (-2)^2 = 20 + (6)^2 + (-2)^2
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x2 + y2 + 4x + 6y − 5 = 0 
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 x2  + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2 
 x2  + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2 
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 2x2 + 2y2 − 24x − 16y − 8 = 0
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 x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
 x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
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 x2 + y2 + 2x − 12y − 9 = 0
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 x2  + 2x + (1)^2 + y2 - 12y  + (-6)^2 = 9 + (1)^2 + (-6)^2
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