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alekssr [168]
3 years ago
10

(5) please find the area of the triangle thank you

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0

Answer:

12times10+5 -3+5-7times305

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2,605 rounded to the nearest hundred......now find the number in the hundreds place...it is the 6....now look at the number to the right of it...if that number is 5 or above, u round the 6 to a 7....but if that number is 4 or below, that 6 stays the same. The number to the right of 6 is 0.....so the 6 stays the same...and ur answer is 2,600.
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7nadin3 [17]

its the first one 6k - 5

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Consider the paragraph proof. Given: D is the midpoint of AB, and E is the midpoint of AC. Prove:DE = BC It is given that D is t
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In a previous exercise we formulated a model for learning in the form of the differential equation dP dt = k(M − P) where P(t) m
GalinKa [24]

Answer:

\frac{dP}{M-P}= kdt

And we can integrate both sides of the equation using the following substitution:

u= M-P, du =-dP

And replacing we got:

\int -\frac{du}{u} = kt +C

-ln (u)= kt+c

If we multiply both sides by -1 we got:

ln (u ) = -kt -c

ln (M-P) = -kt -c

And using exponential in both sides of the equation we got:

M-P = e^{-kt} e^{-c}

And solving for P we got:

P(t) = M- e^{-kt}e^{-c}

And replacing P_o =e^{-c} we got:

P(t) = M - P_o e^{-kt}

We can use the condition P(0)=0 and we got:

0 = M -P_o e^0

And we see that M = P_o and replacing we got:

P= M(1- e^{-kt})

Step-by-step explanation:

For this case we aasume the following differential equation:

\frac{dP}{dt}= k(M-P)

Is a separable differential equation so we can do the following procedure:

\frac{dP}{M-P}= kdt

And we can integrate both sides of the equation using the following substitution:

u= M-P, du =-dP

And replacing we got:

\int -\frac{du}{u} = kt +C

-ln (u)= kt+c

If we multiply both sides by -1 we got:

ln (u ) = -kt -c

ln (M-P) = -kt -c

And using exponential in both sides of the equation we got:

M-P = e^{-kt} e^{-c}

And solving for P we got:

P(t) = M- e^{-kt}e^{-c}

And replacing P_o =e^{-c} we got:

P(t) = M - P_o e^{-kt}

We can use the condition P(0)=0 and we got:

0 = M -P_o e^0

And we see that M = P_o and replacing we got:

P= M(1- e^{-kt})

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3 years ago
Solve for the<br> Proportion for x <br><br><br> I gives brainlieat if u have right answer !
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\frac{x}{12}  =  \frac{25}{60}  \\   60x = 25 \times 12 \\ 60x = 300 \\ x =  \frac{300}{60}  \\  \boxed{x = 5}

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