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3 years ago

(x^3y^2)^2 how do you solve this pls?

Mathematics

1 answer:

Butoxors [25]3 years ago

4 0

Answer: x^6y^4

Step-by-step explanation:

(x^3y^2)^2

Raising to the second power mean multiplying by itself twice

(x^3y^2)^2=(x^3y^2)(x^3y^2)

When you multiply, you add exponents

(x^3y^2)(x^3y^2)=x^3+3 y^2+2

Simplify

x^3+3 y^2+2=x^6y^4

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What is 20 x 10 - 100

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4 years ago

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Step-by-step explanation:

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5 0

3 years ago

Write a simplified expression that represents the perimeter of an irregular quadrilateral with some de lengths (2 1/4t - 5) (4t

hjlf

Answer:

$Perimeter = \frac{39t-4}{4}$

Step-by-step explanation:

Given

$Lengths: (2\frac{1}{4}t - 5), (4t + 3), (1/2t - 1), (3t + 2)$

Required

Determine the perimeter

The perimeter is calculated as the sum of the lengths of the irregular shape.

i.e.

$Perimeter = (2\frac{1}{4}t - 5) + (4t + 3) + (1/2t - 1) + (3t + 2)$

Remove brackets

$Perimeter = 2\frac{1}{4}t - 5 + 4t + 3 + 1/2t - 1 + 3t + 2$

Collect Like Terms

$Perimeter = 2\frac{1}{4}t +4t + 1/2t + 3t - 5 + 3 - 1 + 2$

$Perimeter = 2\frac{1}{4}t +4t + 1/2t + 3t -1$

Convert mixed number to improper fraction.

$Perimeter = \frac{9}{4}t +4t + 1/2t + 3t -1$

Take LCM

$Perimeter = \frac{9t + 16t + 2t + 12t}{4} -1$

$Perimeter = \frac{39t}{4} -1$

Take LCM

$Perimeter = \frac{39t-4}{4}$ <em>--- The perimeter of the shape</em>

8 0

3 years ago

4x^2 +8x-1 what are the roots of the function?

Softa [21]

Answer:

The roots (zeros) are the

x values where the graph intersects the x-axis. To find the roots (zeros), replace and with 0

and solve for

Exact Form:

x=−2±√52

Decimal Form:

x=0.11803398

…,−2.11803398

…

Step-by-step explanation:

4 0

3 years ago