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Cerrena [4.2K]
2 years ago
9

(-2v2+19v-5) - (-4v2+v-23)? How to do????!!!!! Thank you

Mathematics
2 answers:
dalvyx [7]2 years ago
8 0
Is that really a problem of just something random
Stels [109]2 years ago
6 0

Answer:

2v^2+18v+18

Step-by-step explanation:

(-2v^2+19v-5)-(-4v^2+v-23)\\=-2v^2+19v-5+4v^2-v+23\\=2v^2+18v+18

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You are making fruit baskets using 54 apples, 36 oranges, and 73 bananas. Explain why you cannot make identical fruit baskets wi
liq [111]

The bananas are not an equal number so you would not have the same amount unless you take one out.

7 0
3 years ago
Here are two similar rectangles.
asambeis [7]

Answer:

40.32cm^{2}

Step-by-step explanation

4*1.2=4.8

7*1.2=8.4

8.4*4.8=40.32

7 0
3 years ago
Which of the following is equivalent to the expression below?-36A. -6B. 6ОООC. 6D. -6
Vadim26 [7]

SOLUTION;

\sqrt[]{-36}\text{ = }\sqrt[]{(36)(-1)}\text{ = }\sqrt[]{36}\text{ x }\sqrt[]{-1\text{ }}\text{ = 6i}

Recall that the square root of the negative one is "i" meaning that it is a complex number and not a real number.

6 0
1 year ago
A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

8 0
3 years ago
Can someone help me out? (Show work on how to solve)
belka [17]

Answer:

dghggjj

Step-by-step explanation:

s gm knfc JC. jz. jz. .xx nkcmxd I nt☺️️

8 0
3 years ago
Read 2 more answers
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