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Cerrena [4.2K]
2 years ago
9

(-2v2+19v-5) - (-4v2+v-23)? How to do????!!!!! Thank you

Mathematics
2 answers:
dalvyx [7]2 years ago
8 0
Is that really a problem of just something random
Stels [109]2 years ago
6 0

Answer:

2v^2+18v+18

Step-by-step explanation:

(-2v^2+19v-5)-(-4v^2+v-23)\\=-2v^2+19v-5+4v^2-v+23\\=2v^2+18v+18

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5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7BW%7D%20%3D%202" id="TexFormula1" title="\sqrt[4]{W} = 2" alt="\sqrt[4]{W} = 2
solmaris [256]

Answer:

<h2>W = 16</h2>

Step-by-step explanation:

<h3>\sqrt[4]{W}  = 2 </h3>

To find W raise each of the sides of the equation to the power 4 to make W stand alone

That's

<h3>( { \sqrt[4]{W} })^{4}  =  {2}^{4}</h3>

We have

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We have the final answer as

<h3>W = 16</h3>

Hope this helps you

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3 years ago
What is the domain and range of (-6,3), (-1,2), (0,3), (2,4), (5, -1)
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8 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

/

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