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3 years ago

Help me plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics

2 answers:

victus00 [196]3 years ago

6 0

Answer:

for the second space add a zero then multiply 5x5 and 5x2 add that and move the decimal 2 places to the left its infront of your addition answer.

Step-by-step explanation:

tatyana61 [14]3 years ago

4 0

14.75
That’s the answer

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15 points<br>Steps needed

morpeh [17]

It is not a negative so it is 10 because the number can't be big

3 0

3 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

= 0.9821 - .2420

= 0.7401

3 0

3 years ago

Sarah buys 2 candy bars for $1.45. how much would one candy bar cost

sattari [20]

2 = $1.45
1 = $0.725

anything to ask please pm me

4 0

3 years ago

You are 5 feet tall. What is your height in meters (m)?

11111nata11111 [884]

Answer:

1.524

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

4vir4ik [10]

Answer:

(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

$p \pm z*\sigma_{p}$

$\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }$

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

$p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134$

For a 95% two-sided confidence interval, z=±1.96, so

$\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\$

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

$UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787$

The confidence interval is: -∞ ≤ π ≤ 0.0787.

5 0

2 years ago