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4vir4ik [10]
3 years ago
9

What does the graph of Ax)=-(x-3)* +11 look like?

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

  A.  opens downward; vertex (3, 11)

Step-by-step explanation:

The leading coefficient is negative (-1), so we know the parabola opens downward.

The vertex in the form ...

  A(x) = a(x -h)² +k

is (h, k). Comparing to the given equation, we find (h, k) = (3, 11).

The vertex is (3, 11).

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Airida [17]

D is the correct answer I think.

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3 years ago
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Anna11 [10]

Answer:

y/x

Step-by-step explanation:

If x is proportional to y, then:

y = kx, where k is a constant

This can be rearranged to give:

k = y/x

As mentioned, k is a constant, therefore, the answer is y/x

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2 years ago
PLS HELP BRAINLIEST FOR CORRECT ANSWER+20 POINTS
svetoff [14.1K]

Answer:

120 blocks total

Step-by-step explanation:

All of the little cubes have side length 2"  Thus, the 11" height of the box cannot be used entirely:  we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.

Start at the bottom of the box.  The dimensions of the bottom are 12" by 8".  Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide.  We can add 3 more such rows to fill the available 8" width of the box bottom.  That's 6*4, or 24 blocks.

We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.

5 layers times 24 blocks per layer comes to 120 blocks total.

7 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe
algol [13]
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)
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Answer:

Step-by-step explanation:

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