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Free_Kalibri [48]
3 years ago
6

PLEASE HELP

Mathematics
2 answers:
emmainna [20.7K]3 years ago
7 0

Answer:

101 or 36 degrees

Step-by-step explanation:

If you add up the measures of the arcs it is 158. That means BC is 202 degrees. Divide it by 2 to find the angle. For the second answer, remember the question did not specify if the arcs were major or minor so you can flip them around.

oksano4ka [1.4K]3 years ago
6 0

Answer:

m∠BAC is 101° or 36°.

Step-by-step explanation:

Given,

m(\widehat{AB})=115^{\circ}

m(\widehat{AC})=43^{\circ}

To find : The measurement of angle BAC,

Let O be the center of the circle.

Since, here we have to cases ( shown in diagram ),

In Case 1 :

m\angle BOC = 360^{\circ}-[m(\widehat{AB})+m(\widehat{AC})]

=360^{\circ}-(115^{\circ}+43^{\circ})

=360^{\circ}-158^{\circ}

=202^{\circ}

By the central angle theorem,

m\angle BAC = \frac{m\angle BOC}{2}

=\frac{202^{\circ}}{2}=101^{\circ}

In Case 2 :

m\angle BOC = m(\widehat{AB})-m(\widehat{AC})

=115^{\circ}-43^{\circ}

=72^{\circ}

Again by the central angle theorem,

m\angle BAC = \frac{m\angle BOC}{2}

=\frac{72^{\circ}}{2}=36^{\circ}

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The Correct Question is:

Suppose that r1 and r2 are roots of ar² + br + c = 0 and that r1 = r2; then e^(r1t) and e^(r2t) are solutions of the differential equation

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Given the differential equation

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a[r2e^(r2t) - r1e^(r1t )]/(r2 - r1) + [r2²e^(r2t) - r1²e^(r1t )]/(r2 - r1) + c[e^(r2t) - e^(r1t )]/(r2 - r1)

= [(ar2² + br2 + c)e^(r2t) - (ar1² + br1 + c)e^(r1t)]/(r1 - r2)

We know that r1 and r2 are the roots of the auxiliary equation

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aφ'' + bφ' + cφ = 0

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