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Tresset [83]
3 years ago
13

He equation 8 − 4x = 0 has real solution(s)

Mathematics
2 answers:
Rzqust [24]3 years ago
6 0

Answer:

1 real solution, x=2

Step-by-step explanation:

Let's solve for x and see how many solutions exist.

To solve for x, we must get x isolated. To do this, perform the inverse operation to both sides of the equation.

8-4x=0

4x is being subtracted from 8. The inverse, or opposite, of subtraction is addition. Add 4x to both sides.

8-4x+4x=0+4x

8=0+4x

8=4x

x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

8/4=4x/4

8/4=x

2=x

x is equal to 2, therefore there is 1 real solution.

jarptica [38.1K]3 years ago
3 0

Answer:

x=-2

Step-by-step explanation:

subtract 8 from both sides you get -4x=-8

divide by -4

you get x=-2

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The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

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If m1 + m3 = 154°, what is m2? 156° 116° 29° 26°
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Part (2):
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