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2 years ago

Someone please please please please help I need helpppp please

Mathematics

1 answer:

Ugo [173]2 years ago

3 0

Answer:

Step-by-step explanation:

-3.75 + 2.8

= 0.95

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What is the remainder when x^3 -1 is divided by (x+2)

Gnom [1K]

Answer:

Use m athway

Step-by-step explanation:

6 0

2 years ago

Please help im really confused

Dimas [21]

Answer:

A=235 cm 2

Step-by-step explanation:

A1=L x W

A1=9 x 20 180 + 55=235

A1=180cm 2

A2= L x W

A2=11 x 5

A2=55 cm2

7 0

2 years ago

Read 2 more answers

Find the value of x 6x + 12 3x - 3

Shalnov [3]

Answer:

19°

Step-by-step explanation:

Concept Used :-

The measure of a straight line is 180°. So the sum of angles on a straight line is 180° .

Using this ,

$\bf\implies 6x + 12 + 3x - 3 = 180\\\\\bf\implies 9x + 9 = 180\\\\\bf\implies 9x = 180-9 \\\\\bf\implies x =\dfrac{171}{9} \\\\\bf\implies\boxed{\red{\bf x = 19 }}$

<h3>Hence the value of x is 19°</h3>

3 0

2 years ago

Number 11. I need help!!!

Westkost [7]

First add the seconds you have 45 +5+10 seconds which equals 60 seconds or 1 minutes. Now add the minutes 9 + 7 + 12 minutes = 28 minutes then add that 1 minutes that you got from the seconds 28 + 1 minute = 29 minutes 7:40 + 20 minutes = 8:00 + 9 minutes = 8:09 am. So Marsha arrived to school at 8:09 am. Comment if you have any questions.

7 0

2 years ago

I need help with this math question

ICE Princess25 [194]

Answer:

B. 5

Step-by-step explanation:

Step 1: Rewrite the equation a bit

$\frac{7^\frac{3}{4}}{7^\frac{x}{8}}=\sqrt[8]{7}\\7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}$

Step 2: Place a logarithm base 7 on both sides

$7^\frac{3}{4}^-^\frac{x}{8}=7^\frac{1}{8}\\log_77^\frac{3}{4}^-^\frac{x}{8}=log_77^\frac{1}{8}\\(\frac{3}{4}-\frac{x}{8})log_77=\frac{1}{8}log_77\\(\frac{3}{4}-\frac{x}{8})1=\frac{1}{8}1\\\frac{3}{4}-\frac{x}{8}=\frac{1}{8}$

Step 3: Solve for x

$\frac{3}{4}-\frac{x}{8}=\frac{1}{8}\\\frac{6}{8}-\frac{x}{8}=\frac{1}{8}\\-\frac{x}{8}=-\frac{5}{8}\\\frac{x}{8}=\frac{5}{8}\\x=5$

Neat exponent question :)

7 0

1 year ago