When 10x^3+mx^2- x+10 is divided by 5x-3, the quotient is 2x^2+no-2 and the remainder is 4. What is the value of m and n?
1 answer:
Hello,
10x^3+mx^2-x+10=(5x-3)(2x^2+nx-2)+4
=10x^3-6x^2+5nx^2-3nx-10x+6+4
==>
-3n-10=-1 ==>3n=-9==>n=-3
-6+5n=m ==>-6-15=m==>m=-21
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