Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
Using the slope-intercept formula, y=mx+b where m is the slope of the line and b being the y-intercept, by direct substitution, the y-intercept can be directly be obtained,
y=mx+b
14.347 = (4.915)(10.088) + b
therefore, the y-intercept, b = -35.236
Answer: it is 276
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10x7= 70 (Base 1)
10x7= 70 (Base 2)
10x4= 40 (Front)
10x4= 40 (Back)
7x4= 28 (Side 1)
7x4= 28 (Side 2)
---------------------------------
SA= 276
