Answer:
a) e probability that a randomly selected baseball has a weight greater than 5.14 ounces
=P(X>5.14) =(b-x)/(b-a) =(5.155-5.14)/(5.155-5.085)=0.2143
b)
probability that a randomly selected baseball has a circumference less than 9.03 inches
=P(X<9.03) =(x-a)/(b-a) =(9.03-9)/(9.1-9)=0.3
c) probability that a randomly selected baseball will have a weight between 5.11 and 5.13 ounces and a circumference between 9.04 and 9.06 inches
=((5.13-5.11)/(5.155-5.085))*((9.06-9.04)/(9.1-9.0))=0.0571
Positive 3 is the opposite of negtive 3
The balloon assumes the shape of a sphere with a formula of the volume equal to V = 4/3 pi r^3 where r is the radius of the balloon. In this case, we are given with volume of 288 pi in^3. We just substitute the given volume such that the resulting radius that answers the problem is 6 inches.
Answer:
-2+2x=y
Step-by-step explanation:
got it correct on imagine math
