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ruslelena [56]
3 years ago
13

Jessie works at a car manufacturing plant. One day she installed a total of 46 axles, 2 in each car she worked on. She wants to

know how many
cars she installed axles on. You can write an equation that relates the total number of cars, the total number of axles, and the number of axles
installed per car. This equation will have two known quantities and one unknown quantity.
Part A
Write an equation forj, the number of cars Jessie installed axles in.
BIŲ X, Font Sizes
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!!!
Characters used: 0 / 15000
Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

<h2>             23 cars</h2>

Step-by-step explanation:

total number of cars:    x

the total number of axles:    46

and the number of axles  installed per car:   2

2 axles in each car, then total instaled axles:  2•x

2•x = 46

x = 46÷2

x = 23

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Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m &lt; 20
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Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

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To find:

How many possible values of n are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

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Product of roots, \alpha \beta = \frac{C}{A}

Comparing the given equation with standard equation, we get:

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Sum of roots,  \alpha+\beta = -\frac{-m}{1} = m

Product of roots, \alpha \beta = \frac{n}{1} = n

We are given that m  

\alpha and \beta are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

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So, possible combinations and possible value of n (= \alpha \times \beta) are:

1.\ 2,  2\Rightarrow  n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow  n = 6\\3.\ 2, 5 \Rightarrow  n = 10\\4.\ 2,  7\Rightarrow  n = 14\\5.\ 2, 11 \Rightarrow  n = 22\\6.\ 2, 13 \Rightarrow  n = 26\\7.\ 2, 17 \Rightarrow  n = 34\\8.\ 3,  3\Rightarrow  n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow  n = 15\\10.\ 3, 7 \Rightarrow  n = 21\\

11.\ 3,  11\Rightarrow  n = 33\\12.\ 3, 13 \Rightarrow  n = 39\\13.\ 5, 5 \Rightarrow  n = 25\\14.\ 5, 7 \Rightarrow  n = 35\\15.\ 5, 11 \Rightarrow  n = 55\\16.\ 5, 13 \Rightarrow  n = 65\\17.\ 7, 7 \Rightarrow  n = 49\\18.\ 7, 11 \Rightarrow  n = 77

So,as shown above <em>18 values for n are possible.</em>

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