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Novosadov [1.4K]
3 years ago
9

Find the Mean Absolute Deviation:

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

2.33

Explanation:

First find the mean:

1 + 10 + 7 + 6 + 4 + 8 = 36

36 / 6 ( there are 6 total numbers) = the mean is 6

Then subtract the mean from each number:

1 - 6 = -5

10 - 6 = 4

7 - 6 = 1

6 - 6 = 0

4 - 6 = -2

8 - 6 = 2

(don't worry about the negatives)

5 + 4 + 1 + 0 + 2 + 2 = 14

14 / 6 ( again, there are 6 total numbers) = 2.33

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A negative number is not considered a whole number...so ur answer is -229
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4 years ago
In a local city, the temperature at noon is Negative 3 degrees Celsius. The temperature is expected to decrease by 2.5 degrees C
Tresset [83]

Answer:

6

Step-by-step explanation:

18-3 = 15. 15 divided by 2.5 is 6. Hope this helps!

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Compound event is the answer 
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A red apple has mass of 20 grams .you cut it into 5 slices. what about the aplles has changed ?
Nutka1998 [239]
Well you have cut it into smaller pieces so it would be I guess 4 grams now because 20 divided by 5 is 4.
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4 years ago
Please help math questions <br> put number with answers please
natita [175]

Answer:

See below for answers

Step-by-step explanation:

<u>Problem 1</u>

<u />\frac{1}{sin\theta}=2cos\theta\: ; \: 0\leq\theta < 2\pi\\\\1=2sin\theta cos\theta\\\\1=sin2\theta\\\\\frac{\pi}{2}+2\pi n=2\theta\\ \\\frac{\pi}{4}+\pi n=\theta\\ \\\theta=\bigr\{\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\bigr\}

Therefore, the second option is correct.

<u>Problem 2</u>

<u />cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)

0=sinx\\\\x=\pi n\\\\x=0,\pi

0=2sinx+1\\\\-1=2sinx\\\\-\frac{1}{2}=sinx\\ \\x=\frac{7\pi}{6}+2\pi n,\frac{11\pi}{6}+2\pi n\\\\x=\frac{7\pi}{6},\frac{11\pi}{6}

Therefore, the solution set is x=\bigr\{0,\pi,\frac{7\pi}{6},\frac{11\pi}{6}\bigr\}, making the second option correct.

<u>Problem 3</u>

<u />2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0

cosx=0\\\\x=\frac{\pi}{2}+\pi n\\ \\x=90^\circ+180n^\circ\\\\x=90^\circ,270^\circ

2cosx+1=0\\\\2cosx=-1\\\\cosx=-\frac{1}{2}\\\\x=\frac{2\pi}{3}+2\pi n,\frac{4\pi}{3}+2\pi n\\ \\x=120^\circ+360n^\circ,240^\circ+360n^\circ\\\\x=120^\circ,240^\circ

Therefore, the solution set is x=\bigr\{90^\circ,120^\circ,240^\circ,270^\circ\bigr\}, making the fourth option correct

7 0
2 years ago
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