Step-by-step explanation:
hope this helps you to understand
Remark
This is a very interesting question. Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.
y = x (1)
3x + 4y = 12 (2)
Put x in for y in equation 2
3x + 4x = 12
7x = 12
x = 12/7
x = 1.714
y = 1.714
Problem A
<em><u>x intercept</u></em>
The x intercept occurs when y = 0
3x + 4(0) = 12
3x = 12 Divide by 3
x = 12/3
x = 4
the x intercept = (4,0)
<em><u>y intercept</u></em>
The y intercept occurs when x =0
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
y intercept = (0,3)
Problem B
x and y both equal 1.714 so they are also the length of the square's side.
Problem C
See solution above. x =y is the key fact.
x = y = 1.714
1 large slice (41g) of whole grain has 1.7g of fat. This is a little over 4%.
If the perimeter is 39 what you have to do is 39 - 8.5 - 8.5 that will give you 22 and divide 22/2 and that gives you 11. So 11 is the length
Answer:
![\frac{19}{12}\ pounds](https://tex.z-dn.net/?f=%5Cfrac%7B19%7D%7B12%7D%5C%20pounds)
or
![1\frac{7}{12}\ pounds](https://tex.z-dn.net/?f=1%5Cfrac%7B7%7D%7B12%7D%5C%20pounds)
Step-by-step explanation:
<u><em>The correct question is </em></u>
A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many more pounds of plant food does the landscaper need?
Let
x ----> the additional pounds of plant food needed for the landscaper
we know that
The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed
so
The linear equation that represent this problem is
![x+1\frac{1}{4}+\frac{4}{6}=3\frac{4}{8}](https://tex.z-dn.net/?f=x%2B1%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B4%7D%7B6%7D%3D3%5Cfrac%7B4%7D%7B8%7D)
Convert mixed number to an improper fractions
![1\frac{1}{4}=1+\frac{1}{4}=\frac{4*1+1}{4}=\frac{5}{4}](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B4%7D%3D1%2B%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B4%2A1%2B1%7D%7B4%7D%3D%5Cfrac%7B5%7D%7B4%7D)
![3\frac{4}{8}=3+\frac{4}{8}=\frac{3*8+4}{8}=\frac{28}{8}=\frac{14}{4}](https://tex.z-dn.net/?f=3%5Cfrac%7B4%7D%7B8%7D%3D3%2B%5Cfrac%7B4%7D%7B8%7D%3D%5Cfrac%7B3%2A8%2B4%7D%7B8%7D%3D%5Cfrac%7B28%7D%7B8%7D%3D%5Cfrac%7B14%7D%7B4%7D)
Substitute in the expression above
![x+\frac{5}{4}+\frac{4}{6}=\frac{14}{4}](https://tex.z-dn.net/?f=x%2B%5Cfrac%7B5%7D%7B4%7D%2B%5Cfrac%7B4%7D%7B6%7D%3D%5Cfrac%7B14%7D%7B4%7D)
solve for x
Multiply by (4*6) both sides to remove the fractions
![24x+30+16=84](https://tex.z-dn.net/?f=24x%2B30%2B16%3D84)
Combine like terms left side
![24x+46=84](https://tex.z-dn.net/?f=24x%2B46%3D84)
subtract 46 both sides
![24x=84-46](https://tex.z-dn.net/?f=24x%3D84-46)
![24x=38](https://tex.z-dn.net/?f=24x%3D38)
Divide by 24 both sides
![x=\frac{38}{24}\ pounds](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B38%7D%7B24%7D%5C%20pounds)
simplify
![x=\frac{19}{12}\ pounds](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B19%7D%7B12%7D%5C%20pounds)
Convert to mixed number
![\frac{19}{12}\ pounds=\frac{12}{12}+\frac{7}{12}=1\frac{7}{12}\ pounds](https://tex.z-dn.net/?f=%5Cfrac%7B19%7D%7B12%7D%5C%20pounds%3D%5Cfrac%7B12%7D%7B12%7D%2B%5Cfrac%7B7%7D%7B12%7D%3D1%5Cfrac%7B7%7D%7B12%7D%5C%20pounds)