To graph the line, we must first find out the equation for the line in slope-intercept form (y = mx + b). So far, we only have the slope, so the line's equation is y = 3/4x + b. But, by inserting the values of x and y in the point we know, we can find the y - intercept.
4 = 3/4 + b
b = 13/4
That means that the equation of our line is y = 3/4x + 13/4. Now we can graph. But, there is another way to go about (slightly faster too). Since we know the coordinates of 1 point, we can put that line down. Then, since we know that slope is rise over run, we can say, that with a slope of 3/4, one would go 3 points up for every 4 to the right. Now we can go 3 points up and 4 points to the right of point (1,4). That would be (5, 7). Now we can graph (since we have 2 points, or an equation).
The graph looks like this:
The answer your looking for is 33.3%
(it goes on a lot longer but that's just rounded to 1 decimal place)
So I would say 4/18 but it could probably be 18/81 to
2x + 3y = 6 <=>
3y = -2x + 6 <=>
y = -2/3x + 6/3 <=>
y = -2/3x + 2
The answer is the first one.
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>
<span>
Part B:
The mean of a binomial distribution is given by
</span>
<span>
The standard deviation is given by:
</span>
<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
