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Yuri [45]
2 years ago
9

Find the value of x if ∡A and ∡B are supplementary angles.

Mathematics
1 answer:
Elanso [62]2 years ago
3 0

Answer:

x = 30.5

Step-by-step explanation:

Two angles are supplementary when they add up to 180°.

So we know that:

C + D = 180

Supplanting we get:

(3x-44) + (5x-20) = 180

We add up the X's.

8x-44-20 = 180

8x-64 = 180

Then we send 64 to the other side adding:

8x = 180+64

8x = 180+64

8x = 244

And then the 8 goes dividing:

x = 244 : 8

x = 30.5

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Take any three digit number. Reverse its digits and subtract the smaller of the two numbers from the larger. Determine what numb
rjkz [21]

Answer: 11 is the required number that always divides such differences for the following types of numbers.

Step-by-step explanation:

Take any 3 - digit number, say, 325

On reversing its digit it becomes, 523

On subtracting the smaller of the two numbers from the larger,523-325\\\\=198

we can see that 198 is an even number.

take another number say, 629

On reversing its digit, it becomes = 926

On subtracting , we get that

926-629=297

But 297 is not an even number.

But there is one common in both the cases is that both the differences are divisible by 11.

Hence, 11 is the required number that always divides such differences for the following types of numbers.

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3 years ago
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3 0
3 years ago
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Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based
Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}

Then the Taylor series for

f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt

is obtained by integrating the series above:

f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

We have f(0)=0, so C=0 and so

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}

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7 0
3 years ago
A road sign is in the shape of an equilateral triangle with a vertical measurement of 41.2cm. How long is each side?
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What is perimeter of 4 inch square
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4*4 is you answer just times 4*4

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