So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12
so the perimeter = 2(6) + 2(12) = 36
Essentially when people ask you find the solution to system of equation, there asking at what x value do these to graphs intersect. The easiest way to do this is to get a graphing calculator, or desmos and type in the equation and find where they intersect. Heck, even the question says to solve it with a graph, but I'll demonstrate it algebraically.
One way you can do this is set the equation equal to each other. This is because you want to know at what x-value has the same y-value. So we get:
x^2 + 6x + 8 = x + 4
We can then combine like terms, or move everything to one side. So we get:
x^2 + 5x + 4 = 0.
Then we can use the quadratic formula to solve for x.
x=(-5 +/- sqrt(5^2 - 4(1)(4)))/(2(1)
This simplifies into:
(-5 +/- 3)/2
Finally we add and subtract:
(-5 + 3)/2 = x = -1
(-5 - 3)/2 = x = -4
And our solution is x = -1, x = -4
Answer:
Where is the equation for me to solve for x?
Step-by-step explanation:
