Answer:

Step-by-step explanation:
![the \: \sqrt[3]{121} \: is \: not \: a \: perfect \: cube \\ but \\ the \: \sqrt{121} = 11 \to \: is \: a \: perfect \: square \\](https://tex.z-dn.net/?f=the%20%5C%3A%20%20%5Csqrt%5B3%5D%7B121%7D%20%20%5C%3A%20is%20%5C%3A%20not%20%5C%3A%20a%20%5C%3A%20perfect%20%5C%3A%20cube%20%5C%5C%20but%20%5C%5C%20the%20%5C%3A%20%20%5Csqrt%7B121%7D%20%20%3D%2011%20%5Cto%20%5C%3A%20is%20%5C%3A%20a%20%5C%3A%20perfect%20%5C%3A%20square%20%5C%5C%20)
Answer:
Can you please give us figure so that i can help you

What's The Fixed Point? Well, Let's Assume X=0, this is our point.

OR

I'm unaware of the nature of the question, so here are some different ways a fixed point is found based on the merits of the question.
Answer:
Step-by-step explanation:
LOL The graph doesn’t match the y intercept :)
Anyway
If we have point (0,-3) we have a quadratic of
y=ax^2+bx-3 we are given points (-1,0) and (2,0) so
a-b-3=0 and 4a+2b-3=0
4a+2b-3+2(a-b-3)=0
4a+2b-3+2a-2b-6=0
6a-9=0
6a=9
a=1.5, since a-b=3
1.5-b=3
b=-1.5
y=1.5x^2-1.5x-3
I’m pretty sure it is 57?