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aksik [14]
3 years ago
7

Please help with the word problem

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0
The wattage would have to support everything you're running at one time. So the wattage has to be greater than or at least equal to the sum of the watts used. I added what was running and my final answer is...

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A and b are positive integers. Find <img src="https://tex.z-dn.net/?f=-2a%2B3b" id="TexFormula1" title="-2a+3b" alt="-2a+3b" ali
lord [1]

A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.

From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.

Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.

Divide everything by 8 to isolate b and you get that b^2=9.

Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.

Now that we know that a=2 and b=3 just plug them into the equation.

-2(2)+3(3)=?

-4+9=?

5

Sorry about having to use this ^ symbol, the equation maker is not working.

7 0
3 years ago
Bobby jo made 60 holiday cookies. 4/5 of the cookies are for her teachers and the rest are for her family .How many cookies are
Julli [10]

Answer:

12

Step-by-step explanation:

60 divided by 5 is 12, so Bobby jo would give her teachers 48 and 12 to her family

5 0
3 years ago
Assume the line between (-4, 4) and (-4, -4) will form one side of a right triangle. When (-4, 4) is reflected over both axes to
xxMikexx [17]

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B

Step-by-step explanation:

4 0
3 years ago
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What is the value of y in the given triangle?
kondor19780726 [428]

Answer:

Please post a picture of the given triangle.

Step-by-step explanation:

4 0
3 years ago
-104=8x what is x ????
love history [14]
-104=8x \\ \\ - \frac{104}{8} = x \ / \ divide \ each \ side \ by \ 8 \\ \\ -13 = x \ / \ simplify \\ \\ x = -13 \ / \ switch \ solution \ around \\ \\

The final result is, x = -13.
8 0
3 years ago
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