$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y-2=\cfrac{1}{3}(x+6)\implies y-2=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+4$

3 0

2 years ago

Simplify Simplify 6 - 23 + (-9 + 5) · 2.

Vlad [161]

Answer:

The answer is −42

7 0

2 years ago

Find the value of x and y.<br><br>help me out ASAP!!

il63 [147K]

Step-by-step explanation:

13x + 15 = 19x - 9 ( being opposite sides of parallelogram)

19x - 13x = 15 + 9

6x = 24

x = 24 / 6

x = 4

4y + 7° + 10y - 37° = 180° {being co-interior angles }

14y = 180° - 7° + 37°

14y = 210°

y = 210°/ 14

y = 15°

Hope it will help :)

3 0

2 years ago