$24.89
23x0.0822=1.89
23+1.89=24.89
Answer: c. –1 and .1587
Step-by-step explanation:
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since Alternative hypothesis is left-tailed ,so the test must be a left tailed test .
Z -Test statistic for proportion = 
, where p= population proportion
= sample proportions
n= Sample size.
Let x be the number of successes.
For n= 40 and x= 11
Then , 
By using z-table ,
P-value for left-tailed test = P(z<-1)= 1-P(z<1) [∵ P(Z<-z)= 1-P(Z<z) ]
= 1-0.8413
=0.1587
Hence, the -score and P-value are <u>–1 and 0.1587</u> .
So the correct option is c. –1 and .1587
Answer:
PEMDAS is a great way to figure this out!
P - Parenthesies
E - Exponents
M - Multiplcation
D - Division
A - Addition
S - Subtraction
Follow this order and you should be good to go! Here's how I would follow this in this equation.
11x-2-3(1-7x)^2+(x+1)
First, parentheses
The 3 directly next to the parenthesies shows that everything inside of the () needs to be multiplied by 3.
-3*1 and -3*-7x (don't forget the negative)
This gives us 11x-2+(-3+21x)^2+(x+1)
Now distribute the exponents to everything inside of the parentheses.
11x-2+-3^2+21x^2+(x+1)
now solve the numbers with exponents without a variable.
3^2 = 3*3 = 9
combine any numbers without a variable outside of parentheses
11x-2+9+21x^2+(x+1)
11x+7+21x^2+(x+1)
From here, what I would do is divide the whole equation by 2
5.5x+3.5+21x+(.5x+.5)
now combine x values outside of parentheses
3.5+26.5x+(.5x+.5)
I believe this would be the simplest form, but please do correct me if I'm wrong or made any errors
Answer:
Step-by-step explanation:
The null and alternative hypothesis are usually used in hypothesis testing to present the claim being tested as give in terms of the mean or proportion :
Given that the mean score of high school students is 10 ; using a sample of 50 students, a mean of 8 was obtained ; we could want to test the claim that the mean score is less than 10.
Here; population mean, μ = 10 ; the claim is now that, μ < 10 based on what was observed about the sample.
H0 : μ = 10
H0 : μ < 10
If we wanted to test If the mean was greater than 10 ; then the sign is reversed
H0 : μ = 10
H0 : μ > 10
If we wanted to test If the score is just different from the mean score stated ; (it may be less than or greater than)
H0 : μ = 10
H0 : μ ≠ 10
