Question

Cindy is selling circus tickets. On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. On the second day she sells 8 adult tickets and 4 children tickets for the total 130. Determine the cost of adult and child tickets. Used a to represent adult and c to represent child tickets. Write an equation to represent the sales of day 1 and day 2. Used the elimination method.

Answer 1

Answer: Children tickets cost 7.50

Adult tickets cost 12.50

Step-by-step explanation:

Let a represent adult tickets

Let c represent child tickets

On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:

6a + 5c = 112.50 ...... equation i

On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:

8a + 4c = 130 ....... equation ii

6a + 5c = 112.50 ...... equation i

8a + 4c = 130 ....... equation ii

Multiply equation i by 4

Multiply equation ii by 5

24a + 20c = 450 ........ equation iii

40a + 20c = 650 ......... equation iv

Subtract iii from iv

16a = 200

a = 200/16

a = 12.50

Adult tickets cost 12.50

From equation ii,

8a + 4c = 130

8(12.50) + 4c = 130

100 + 4c = 130

4c = 130 - 100

4c = 30

c = 30/4

c = 7.50

Children tickets cost 7.50