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3 years ago

What is the midpoint between (-2, -3) and (1, 0.5)

Mathematics

1 answer:

Art [367]3 years ago

3 0

Answer:

(-1/2,-1.25)

Step-by-step explanation:

Once you plot the points, you should be able to find the midpoint formula.

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What is the slope of the line ?

nikitadnepr [17]

Answer:

-3/4

Step-by-step explanation:

To find the slope of a line, you need to see how much it "rises" over a certain amount of "run". In other words, for a given amount of distance traveled along the x axis, how much it traveled vertically along the y axis. In this line, for every 4 units moved to the right, the line goes up by -3 units. Therefore, the slope of the line is -3/4. Hope this helps!

4 0

3 years ago

Read 2 more answers

Work out the area of a rectangle with base,b= 32mm and perimeter,P= 78mm.

Nataly_w [17]

Answer:

224

Step-by-step explanation:

b = 32, h = 7 is the solution to P = 78. Hence, 7*32 = 224 is the answer

7 0

3 years ago

A store buys jeans from the manufacturer for $30 each and sells them for a 50% profit. At the end of the season, the store reduc

Ipatiy [6.2K]

50% of $30.00 = $15.00 profit during season
The store does not make a profit on the sale of the jeans at the end of season because the store sells the jeans for $30.00 + $15.00 = $45.00
per jean. 50% sale reduces the price to half. $22.50. There will be a loss since the store purchased the jeans for $30.00

6 0

4 years ago

Help with this question ASAP!

user100 [1]

Answer:

After 4s

Step-by-step explanation:

Given the ball is initially projected upwards with a velocity of 64ft per sec and we are required to find the time at which it reaches the ground .There are many approaches to solve this problem we will follow this one:

It is also known as the time of flight for the ball which can be found by doubling the time taken for the ball to reach to its maximum height or the point where velocity is zero.

Now $h(t)=-16\times t^{2} +v_{0} \times t+h_{0}$

For the time taken to reach the max height $\frac{dh}{dt} =0$ .

Which implies that -32t+v=0.

∴Time taken to travel halfway through the path =2sec.

∴total time = $2\times 2=4sec$

4 0

3 years ago

(1 point) (a) Find the point Q that is a distance 0.1 from the point P=(6,6) in the direction of v=⟨−1,1⟩. Give five decimal pla

natima [27]

Answer:

following are the solution to the given points:

Step-by-step explanation:

In point a:

$\vec{v} = -\vec{1 i} +\vec{1j}\\\\|\vec{v}| = \sqrt{-1^2+1^2}$

$=\sqrt{1+1}\\\\=\sqrt{2}$

calculating unit vector:

$\frac{\vec{v}}{|\vec{v}|} = \frac{-1i+1j}{\sqrt{2}}$

the point Q is at a distance h from P(6,6) Here, h=0.1

$a=-6+O.1 \times \frac{-1}{\sqrt{2}}\\\\= 5.92928 \\\\b= 6+O.1 \times \frac{-1}{\sqrt{2}} \\\\= 6.07071$

the value of Q= (5.92928 ,6.07071 )

In point b:

Calculating the directional derivative of $f (x, y) = \sqrt{x+3y}$ at P in the direction of $\vec{v}$

$f_{PQ} (P) =\fracx{f(Q)-f(P)}{h}\\\\$

$=\frac{f(5.92928 ,6.07071)-f(6,6)}{0.1}\\\\=\frac{\sqrt{(5.92928+ 3 \times 6.07071)}-\sqrt{(6+ 3\times 6)}}{0.1}\\\\= \frac{0.197651557}{0.1}\\\\= 1.97651557$

$\vec{v} = 1.97651557$

In point C:

Computing the directional derivative using the partial derivatives of f.

$f_x(x,y)= \frac{1}{2 \sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{2 \sqrt{22}}\\\\f_x(x,y)= \frac{1}{\sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{\sqrt{22}}\\\\f_{(PQ)}(P)= (f_x \vec{i} + f_y \vec{j}) \cdot \frac{\vec{v}}{|\vec{v}|}\\\\= (\frac{1}{2 \sqrt{22}}\vec{i} + \frac{1}{\sqrt{22}} \vec{j}) \cdot \frac{-1}{\sqrt{2}}\vec{i} + \frac{1}{\sqrt{2}} \vec{j}$

4 0

3 years ago