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lianna [129]
3 years ago
5

What is the y-intercept of this table? yall pls i need correct answers

Mathematics
1 answer:
jarptica [38.1K]3 years ago
4 0

Answer:

21

Step-by-step explanation:

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Step-by-step explanation:

dfs

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3 years ago
Triangle BCD is equivalent AG=1.find the perimeter of BCD
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AG=1 => BG=3 => CG=sqrt3 => CD = 2sqrt3 => perimeter = 3*CD= 6sqrt3
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4.
Fittoniya [83]

Answer:

60

Step-by-step explanation:

200*0.30=60

Multiply the percent's by the total cost.

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2 years ago
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Peter owned a juice shop. He sold a cup of lemon juice for $1.25 and a cup of apple juice for $2.50. If Peter sold a total of 15
meriva

Answer:

You have to add them then divide by the number of cups

Step-by-step explanation:

6 0
3 years ago
Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Spr
NeX [460]

Answer:

20.2057 Units.

Step-by-step explanation:

First, we determine the length of the cable.

Distance between Centerville (8,0) and point (x,0) is given as:  

  • \sqrt{(8-x)}^2=8-x

Distance between point (x,0) and Springfield(0,7) is:

\sqrt{(7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}

Distance between point (x,0) and Shelvyfield(0,-7) is:

\sqrt{(-7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}

Therefore the Length of the Cable L(x)

  • L(x)=(8-x)+2\sqrt{(7)^2+(x)^{2}}

To find the critical point, we set the derivative of L(x)=0

L^{'}(x)=-1+\frac{2x}{\sqrt{\left( 49 - x^{2}\right) }}

\frac{-\sqrt{\left( 49 - x^{2}\right)}+2x}{\sqrt{\left( 49 - x^{2}\right)}}=0\\-\sqrt{\left( 49 - x^{2}\right)}+2x=0\\\sqrt{\left( 49 - x^{2}\right)}=2x\\(\sqrt{\left( 49 - x^{2}\right)})^2=(2x)^2\\49 - x^{2}=4x^2\\49=5x^2\\x^2=\frac{49}{5}\\x= 3.1305

To verify that L(x) has a minimum at this critical number we compute the second derivative L″(x) and find its value at the critical number.

L^{''}(x)=\frac{\left( 98\right) \,\sqrt{\left( 49 - x^{2}\right) }}{{\left( 7 - x\right) }^{2}\,{\left( 7+x\right) }^{2}}\\At \:x=3.1305, L^{''}=0.3993

Since L^{''}(x)  is positive, the minimum point of L(x) exists.

Next, we find the minimum length by substituting z=3.1305 into L(x)

L(3.1305)=(8-3.1305)+2\sqrt{(7)^2+(3.1305)^{2}}

Minimum Length, L=20.2057

The minimum length of the cable is 20.2057 Units.

6 0
3 years ago
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