Question

A brand of cereal had 1.2 milligrams (mg) of iron per serving. Then they changed their recipe so they had 1.8 milligrams (mg) of iron per serving. What was percent increase in iron?

Answer 1

Answer:

The percent increase in iron = 50 %

Step-by-step explanation:

Initial amount of iron per serving = 1.2 mg

After an increase the amount of iron per serving = 1.8 mg

Increase in  the amount of iron per serving = 1.8 - 1.2 = 0.6 mg

Percent increase in iron is calculated as

$% increase = \frac{Final amont - initial amount }{initial amount}$$Change = \frac{Final \ amount - initial \ amount }{initial \ amount} (100)$

Put the values in above formula we get

$\frac{0.6}{1.2} (100)$ =   50 %

Therefore the percent increase in iron = 50 %