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mixas84 [53]
3 years ago
15

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly and at a constant rate. After 8 88 mon

ths, he weighed 138 138138 kilograms. He started at 90 9090 kilograms. Let y yy represent the sumo wrestler's weight (in kilograms) after x xx months. Complete the equation for the relationship between the weight and number of months.
Mathematics
1 answer:
Aliun [14]3 years ago
3 0

Answer:

Equation for the relationship between the weight and number of months -

W(t) = W(0) + 6 * t

Step-by-step explanation:

Given

The initial weight of young sumo wrestler just before he decide to gain more weight is equal to 90 kilo grams.

The new weight of young sumo wrestler after eight months is equal to 138 kilo grams.

Weight gained by sumo wrestler during the period of eight months

138 -90\\= 48

The rate at which weight was gained

\frac{48}{8}

6 kilo grams per month

Let W(t) depict the weight after 8 months

t depict the time period in moths

So the equation would be

W(t) = W(0) + 6 * t

Where

W(0) = Initial weight before 8 months

t = time in months

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Which rule represents the table's values?<br> y = 2x<br> y=-2x<br> y=-12%<br> V = -2x + 1
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Answer:

Therefore the required rule for the given table is

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Step-by-step explanation:

Given :

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x          y

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To Find :

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y=-2x

For first case

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y=-2\times 7 =-14 as shown in the table

For third case

Put x = 8 in the rule we get

y=-2\times 8 =-16 as shown in the table

For fourth case

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7 0
4 years ago
3) Solve the equation. Show steps. -406 = c + 430​
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Step-by-step explanation:

Check out the attachment below:

8 0
3 years ago
Please help me thank you
Lunna [17]

Answer:

      418

Sn = ∑ 3 +4(n-1)

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Step-by-step explanation:

3,7,11,15,.....1671

a1 =3

d = 4  (7-3=4)

an = a1 + d(n-1)

an = 3 +4(n-1)

We need to determine the last term

1671 = 3 +4(n-1)

Subtract 3

1671-3 = 3-3 +4(n-1)

1668 = 4(n-1)

divide by 4

1668/4 = 4(n-1)/4

417 = n-1

Add 1 to each side

418 = n

      418

Sn = ∑ a1 +d(n-1)

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      418

Sn = ∑ 3 +4(n-1)

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8 0
3 years ago
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