Find the absolute extrema of the function on the closed interval. f(x) = sin 2x, [0, 2π]
1 answer:
Answer:
Minimum -1, maximum 1.
At points (3π/4. -1) and (π/4 , 1)
Step-by-step explanation:
The maximum value for the sine of an angle is 1 and the minimum is -1.
The angle will have values of π/2 and 3π/2 at these points.
As the angle is 2x the angle values will be π/4 and 3π/4.
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