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Vladimir [108]
2 years ago
14

Find the length of chord AD

Mathematics
1 answer:
Ket [755]2 years ago
7 0

9514 1404 393

Answer:

  AD = 15

Step-by-step explanation:

The products of the segment lengths are the same.

  (x -2)(x +7) = 4(2x -1)

  x^2 +5x -14 = 8x -4

  x^2 -3x -10 = 0

  (x -5)(x +2) = 0

The positive solution is x=5.

Chord AD is ...

  (x -2) +(x +7) = 2x +5 = 2(5) +5 = 15

Chord AD is 15 units long.

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Step-by-step explanation:

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For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

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and subtracting 5 from both sides, we have

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3 0
2 years ago
What is the solution to this equation? <br> 3x-x+8+5x-2=10
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combine like terms on the left, then add or subtract as asked
(3x - x + 5x) + (8 - 2) = 10

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divide both sides by 7

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Hope this helps! :)
7 0
3 years ago
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Answer:

12

Step-by-step explanation:

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