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lora16 [44]
3 years ago
10

Please help this is too hard for me

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
128, 4x4x8= 128 square
UNO [17]3 years ago
3 0
The answer is 128 cause 8×4×4=128
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The function h is defined by H(x)=x^2-6 <br><br> find h(5x).<br><br> H(5x)=
Stolb23 [73]

h(x)\ \ =\ x^2-6\\.\ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\\h(5x)=(5x)^2-6=(5)^2(x)^2-6=25x^2-6

3 0
2 years ago
What is the value of the sin3x/6x; as x approaches to zero
nikklg [1K]

Step-by-step explanation:

When x = 0,

sin3x / 6x = 0 / 0, which is an indeterminate form.

Hence we use L'Hospital's rule:

d/dx (sin3x) = 3cos3x

d/dx (6x) = 6

Now we have 3cos3x / 6 or 0.5cos3x.

When x = 0, 0.5cos3x = 0.5(1) = 0.5.

Hence the limit is 0.5.

6 0
3 years ago
(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
frutty [35]

Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

4y''=-25y

For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

4 0
2 years ago
Write the equation of a line that passes through (2,6) and (-2,2)
Viktor [21]

Answer:

y = x + 4

Step-by-step explanation:

The equation of the line is

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Give points

( 2 , 6) ( -2 ,2)

x1 = 2

y1 = 6

x2 = -2

y2 = 2

m = 2 - 6 / -2 - 2

m = -4 / -4

m = 1

y = mx + c

y = 1x + c

y = x + c

Step 2: sub any of the two points given into the equation

( 2 , 6)

x = 2

y = 6

y = x + c

6 = 2 + c

6 - 2 = c

c = 4

Step 3: sub c into the equation

y = x + 4

The equation of the line is

y = x + 4

5 0
3 years ago
What is the value of x?<br><br>Enter your answer in the box. <br><br>x =​
balu736 [363]

Answer:

x=3

Step-by-step explanation:

BC=6

cos(60)=×÷6

×=3

8 0
3 years ago
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