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3 years ago

Pls help ASAP!!!!! plss anyone!!!!

Mathematics

1 answer:

vfiekz [6]3 years ago

5 0

Answer:

a = 117°

c = 117°

d = 63°

c = 87°

a = 60°

b = 30°

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Simplify 6 -square root of 15 divided by 2

egoroff_w [7]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

Rewrite! Write an new and equivalent equation that is easier to solve

Marysya12 [62]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - an equation in a standard form

To do - simplify the equation so as to obtain an easier one

Since the equation provided isn't in it's general form , let's first convert it ~

General form of a Linear equation -

$\bold{ax + b = 0}$

The equation after getting converted will be as follows ~

$- 7 + ( \frac{4x + 2}{2} ) = 8 \\ \\ \implies \: \frac{ - 14 + 4x + 2}{2} = 8 \\ \\ \implies \: - 14 + 4x + 2 = 16 \\ \\ \implies \: 4x = 16 + 14 - 2 \\ \\ \implies \: 4x = 28 \\ \\\bold{ General \: form \: \dashrightarrow \: 4x - 28 = 0}$

hope helpful ~

6 0

2 years ago

A hovercraft takes off from a platform. It’s height (in meters), x seconds is modeled by h(x)=-(x-11)(x+3). What is the height o

Eddi Din [679]

Answer:

The height of the hovercraft at the time of takeoff is 33 meters.

Step-by-step explanation:

Height of hovercraft x seconds after takeoff = h(x) = -(x - 11)(x + 3)

Height after takeoff is = h(0) = -(0 - 11)(0 + 3) = -(-11)(3) = 33

So the correct answer is 33 meters. The height of the hover craft at the time of the takeoff is 33 metres.

Answer: 33 meters.

Please mark brainliest

Hope this helps

6 0

3 years ago

Can you please answer this question

schepotkina [342]

Answer:

1/40

219/250

69/16

Step-by-step explanation:

0.025=(025)/(1000)=1/40

0.876=876/1000=219/250

4.3125=43125/10000=1725/400=69/16

4 0

3 years ago

19. Use Gauss-Jordan elimination to solve the following system of equations. 3x + 5y = 7 6x − y = −8

MrRa [10]

$\left[\begin{array}{cc}3&5\\6&-1\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}7\\-8\end{array}\right]\\\left[\begin{array}{cc|c}3&5 &7\\ 6& -1 & -8\end{array}\right] \rightarrow \left[\begin{array}{cc|c}3&5& 7\\0&-11 & -22\end{array}\right] \rightarrow \left[\begin{array}{cc|c}3&5& 7\\0&1 & 2\end{array}\right]\\3x +5y = 7\\\\y = 2\\\therefore x = -1$

6 0

3 years ago