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meriva
3 years ago
14

Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is a viable solut

ion if x represents the number of days that a library book is late and y represents the total fee?
a. (–3, –0.90)
b. (–2.5, –0.75)
c.(4.5, 1.35)
d. (8, 2.40)
Mathematics
2 answers:
Verizon [17]3 years ago
8 0

Answer:

The correct answer would be (8,2.40).

Step-by-step explanation:

Option one(-3, -0.9) and two (-2.5, -0.75) Would not be a viable solution because the value of number of days can not be negative and in option one and two, value of days -3 and -2.5 is negative.

Option three(4.5, 1.35) can not be correct because library charges fee for a full day so the number for days would be a whole number. Library would not charge for 4.5 days, they would either charge of 4 days or 5 days because 4.5 is not an whole number.

Option four(8, 2.40) is the correct answer because it satisfies our equation;

Y= 0.30 * X

2.40= 0.30 * 8

2.40 = 2.40

hope this helps :)

padilas [110]3 years ago
3 0

D is the right answer

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leva [86]

Answer:

The final balance would be $1,038 after 4 years and 5 months.

Step-by-step explanation:

The final balance would be $1,038 and the total compound interest would be $213.

5 0
2 years ago
There are 40 runners in a race. How many ways can the runners finish​ first, second, and​ third?
k0ka [10]

Answer:

117600

Step-by-step explanation:

50 x 49 x 48 = 117,600 ways

You have 50 possible for 1st, 49 for 2nd, 48 for 3rd

or

Permutations 50P3 = 117,600

5 0
3 years ago
Pls help with qn 13!!!!
balandron [24]
4243.6-4000=243.6/4000= 0.06

Interest rate 0.06%
4 0
3 years ago
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zubka84 [21]

The HCF are

  • 3
  • 6
  • 3
  • 12
  • 6
  • 18
  • 8
  • 14
  • 15

<h3>What is HCF?</h3>

This is the common factor that is the highest that a group of numbers can have in common.

1. 6 and 15

factors of 6 =  1, 2, 3, 6

factors of 15:  1, 3, 5, 15

The HCF is the number they have in common = 3

2. 12 and 18

The factors of 12:  1, 2, 3, 4, 6, 12

The factors of 18:  1, 2, 3, 6, 9, 18

The HCF = 6

3. 15 and 24

Factors of 15:  1, 3, 5, 15

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The HCF = 3

4. 24 and 36

The factors of 24:  1, 2, 3, 4, 6, 8, 12, 24

The factors of 36:  1, 2, 3, 4, 6, 9, 12, 18, 36

The HCF :  12

5. 30 and 48

The factors of 30:  1, 2, 3, 5, 6, 10, 15, 30

The factors of 48:  1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The HCF = 6

6. 36 and 54

The factors of 36:  1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 54:  1, 2, 3, 6, 9, 18, 27, 54

The hcf = 18

7. 32,40 and 56

The factors of 32:  1, 2, 4, 8, 16, 32

The factors of 40:  1, 2, 4, 5, 8, 10, 20, 40

The factors of 56:  1, 2, 4, 7, 8, 14, 28, 56

The HCF is 8

8. 28,42 and 70

The factors of 28:  1, 2, 4, 7, 14, 28

The factors of 42:  1, 2, 3, 6, 7, 14, 21, 42

The factors of 70:  1, 2, 5, 7, 10, 14, 35, 70

The HCF = 14

9. 30,75 and 90

The factors of 30:  1, 2, 3, 5, 6, 10, 15, 30

The factors of 75:  1, 3, 5, 15, 25, 75

The factors of 90:  1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The HCF is 15

Read more on HCF here;

brainly.com/question/21504246

#SPJ1

8 0
2 years ago
How do I solve fro r and q?<br><br> 9r+q=13<br> 3r+2q=-4
olga55 [171]
One way to solve the system of equations would be to solve for q (in terms of r) in the first equation to get:
9r + q = 13
q = 13 - 9r

Then, take the value for q you just found and insert it into the second equation:
3r + 2(13-9r) = -4

Then simplify and solve:
3r + 26 - 18r = -4
-15r = -30
r = 2

Now that you have the value for r, plug it into either of the original equations and solve for q:
9r + q = 13
9(2) + q =13
18 + q = 13
q = -5

r = 2; q = -5
7 0
3 years ago
Read 2 more answers
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