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3 years ago

Is someone able to help me with this please I don't understand.

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

Step-by-step explanation: if you pay attention to this answer its for points thanks

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Someone pls pls pls help

Svetllana [295]

Answer:

$I= \frac{1}{ {2}^{t} }$

Step-by-step explanation:

Please see the attached picture for the full solution.

7 0

3 years ago

I have to make two paragraphs each one about jobs that contain math. The jobs i have to use are store manager and Game progra

jok3333 [9.3K]

A store manager use numbers by having to check each register. Another way a store manager uses numbers is by counting money. And knowing what food (ex. meats, cereals,eggs,milk) is coming in amg when.
A game programmer uses number with his/her job is by have to code their character to move. Another way a game programmer uses numbers is by having to know how to add codes to there game.

8 0

3 years ago

Read 2 more answers

Evaluate integral _C x ds, where C is

borishaifa [10]

Answer:

a. $\mathbf{36 \sqrt{5}}$

b. $\mathbf{ \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}$

Step-by-step explanation:

Evaluate integral _C x ds where C is

a. the straight line segment x = t, y = t/2, from (0, 0) to (12, 6)

i . e

$\int \limits _c \ x \ ds$

where;

x = t , y = t/2

the derivative of x with respect to t is:

$\dfrac{dx}{dt}= 1$

the derivative of y with respect to t is:

$\dfrac{dy}{dt}= \dfrac{1}{2}$

and t varies from 0 to 12.

we all know that:

$ds=\sqrt{ (\dfrac{dx}{dt})^2 + ( \dfrac{dy}{dt} )^2}} \ \ dt$

∴

$\int \limits _c \ x \ ds = \int \limits ^{12}_{t=0} \ t \ \sqrt{1+(\dfrac{1}{2})^2} \ dt$

$= \int \limits ^{12}_{0} \ \dfrac{\sqrt{5}}{2}(\dfrac{t^2}{2}) \ dt$

$= \dfrac{\sqrt{5}}{2} \ \ [\dfrac{t^2}{2}]^{12}_0$

$= \dfrac{\sqrt{5}}{4}\times 144$

= $\mathbf{36 \sqrt{5}}$

b. the parabolic curve x = t, y = 3t^2, from (0, 0) to (2, 12)

Given that:

x = t ; y = 3t²

the derivative of x with respect to t is:

$\dfrac{dx}{dt}= 1$

the derivative of y with respect to t is:

$\dfrac{dy}{dt} = 6t$

$ds = \sqrt{1+36 \ t^2} \ dt$

Hence; the integral _C x ds is:

$\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt$

Let consider u to be equal to 1 + 36t²

1 + 36t² = u

Then, the differential of t with respect to u is :

76 tdt = du

$tdt = \dfrac{du}{76}$

The upper limit of the integral is = 1 + 36× 2² = 1 + 36×4= 145

Thus;

$\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt$

$\mathtt{= \int \limits ^{145}_{0} \sqrt{u} \ \dfrac{1}{72} \ du}$

$= \dfrac{1}{72} \times \dfrac{2}{3} \begin {pmatrix} u^{3/2} \end {pmatrix} ^{145}_{1}$

$\mathtt{= \dfrac{2}{216} [ 145 \sqrt{145} - 1]}$

$\mathbf{= \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}$

5 0

4 years ago

Find the solution for 30 − 5n ≤ 25.<br> 1 n ≤ -1<br> 2 n ≤ -11<br> 3 n ≥ -11<br> 4 n ≥ 1

Anit [1.1K]

Answer:

n>=1

Step-by-step explanation:

30-5n<=25

5n<=30-25

5n<=5

n<=5/5

n<=1

n>=1

3 0

3 years ago

Name the set of numbers to each number that belongs. Natural, Whole, Integers, and Rational numbers.

ryzh [129]

1. rational
2. rational
3. natural, whole, integer, rational
4. integer, rational
5. rational
6. integer, rational
7. rational
8. rational
9. natural,whole,integer,rational
10. rational

6 0

3 years ago