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2 years ago

14

What is the straight-line distance between (2, -4) and (-3, 8) on a coordinate grid?

1 answer:

Scrat [10]2 years ago

6 0

It is most likely 14 units so it would be A. I think.

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1. Tanner collected 360 cans and bottles while fundraising for his baseball team. This was 40% of what Reggie collected. How man

Inessa05 [86]

1. 360*0.40=144
so they said 40% reggie collected main mor than 40% collected so you need to do add like 360+144=504
the answer 504

2. you need to do new to old
the new is 15 old is 799
799-15=784x100
the high number is 799
so you need to do 799 divided by 100=7.99
now 784 divided by 7.99=98.12
the answer is 98.12

3 0

2 years ago

If x is Equal to 7, what is 7 divided by 3 and round it up

VikaD [51]

Answer:

2.3 or 2

Step-by-step explanation:

7 0

2 years ago

X (27-x) = 182<br>Please help me by solving this!

pentagon [3]

I hope this helps you..!

3 0

2 years ago

The answer for this lol thanks

Olenka [21]

Answer:

x times (x+1).

If it's wrong, then I'm an idiot.

Step-by-step explanation:

5 0

2 years ago

To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x

Fiesta28 [93]

Given function is

$f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.$

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

$kx^2-5$

so RHD= $k(-4)^2-5$

Now set both equal

$k(-4)^2-5=3(-4)+k$

$16k-5=-12+k$

$16k-k=-12+5$

$15k=-7$

$k=-\frac{7}{15}$

k=-0.47

<u>Hence final answer is -0.47.</u>

7 0

2 years ago