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s344n2d4d5 [400]
2 years ago
9

Calculate the area of the regular pentagon below:

Mathematics
2 answers:
KIM [24]2 years ago
5 0
The answer is 858.55 because A=145(5+25)a2
ch4aika [34]2 years ago
5 0

Answer:

888888555555555558888888888888888888888888888888888888888899....555 C lol fllow my tt tvdlover21 and helpingyou2shift

Step-by-step explanation:

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The current of a river is 3 miles per hour. A boat travels to a point 176 miles upstream and 176 miles back in 19 hours. What is
serious [3.7K]

Answer:

If I am understanding your question, the total upstream is 8 miles and another 8 miles downstream.

Let s = the speed of the boat in still water

d = rt

8 = 5(s + 3)  downstream

8 = 5s + 15  equation 1

8 = 5(s - 3)   upstream

8 = 5s - 15    Add equation 1

8 = 5s + 15 

16 = 10s    Divide both sides by 10.

s = 16/10 = 8/5 = 1.6 mph

 

4 0
2 years ago
Evaluate the integral by making an appropriate change of variables.
VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

<em>u</em> = <em>y</em> + <em>x</em>

<em>v</em> = <em>y</em> - <em>x</em>

<em />

Solving for <em>x</em> and <em>y</em>, we would have

<em>x</em> = (<em>u</em> - <em>v</em>)/2

<em>y</em> = (<em>u</em> + <em>v</em>)/2

in which case the Jacobian and its determinant are

J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12

The trapezoid <em>R</em> has two of its edges on the lines <em>x</em> + <em>y</em> = 8 and <em>x</em> + <em>y</em> = 9, so right away, we have 8 ≤ <em>u</em> ≤ 9.

Then for <em>v</em>, we observe that when <em>x</em> = 0 (the lowest edge of <em>R</em>), <em>v</em> = <em>y</em> ; similarly, when <em>y</em> = 0 (the leftmost edge of <em>R</em>), <em>v</em> = -<em>x</em>. So

-<em>x</em> ≤ <em>v</em> ≤ <em>y</em>

-(<em>u</em> - <em>v</em>)/2 ≤ <em>v</em> ≤ (<em>u</em> + <em>v</em>)/2

-<em>u</em> + <em>v</em> ≤ 2<em>v</em> ≤ <em>u</em> + <em>v</em>

-<em>u</em> ≤ <em>v</em> ≤ <em>u</em>

<em />

So, the integral becomes

\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du

=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du

=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du

=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}

4 0
2 years ago
Kelvin finished $\frac{2}{3}$ 2 3​​ of his test in a $\frac{1}{2}$ 1 2​​ hour. Express this rate in hours per test.
svet-max [94.6K]

Complete Question

Kelvin finished 2/3​​ of his test in a 1/2​​ hour. Express this rate in hours per test.

Answer:

3/4 hours per test

Step-by-step explanation:

2/3 of his test = 1/2 hour

This rate in hours per test is calculated as:

x = 1/2 /2/3

x = 1/2 hour ÷ 2/3 test

x = 1/2 × 3/2

x = 3/4 hours per test

This rate in hours per test is given as 3/4 hours per test

4 0
2 years ago
Please help me not hard please
IrinaVladis [17]

Answer:

I think it's A

Step-by-step explanation:

8 0
3 years ago
a figure was rotated around a vertical line segment resulting in the object below. which of the figues was rotated
oksano4ka [1.4K]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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