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masha68 [24]
2 years ago
14

No links pls just answer the question direct.

Mathematics
1 answer:
NeTakaya2 years ago
3 0
Formula:

(3.14)r^2

Larger one:

(3.14)(3)^2

28.26 * 13

367.38 in^2

Smaller one:

(3.14)(3)^2

28.26 * 8

226.08 in^2

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Factor completely 2x^3-18x
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Answer:

2x(x+3)(x-3)

Step-by-step explanation:

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What is the percentage of 1669 out of 25
fomenos

Answer:

6676%

Step-by-step explanation:

25 times 4 = 100

1669 times 4 = 6676

6676/100 = 6676%

8 0
2 years ago
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How do you right -6x-42=-16y in standard form?
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16y=6x+42
16/16y=6x/16+42/16
y= 3x/8 + 21/8 
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Joe pays $26.78 for 6.5 gallons of gas.
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$4.12

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3 years ago
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A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
3 years ago
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