From the coordinate plane, the podium that could be located relative to the center will be B. 288 feet west.
<h3>Coordinate plane</h3>
From the complete information, there is a park in Washington and the event planner plots the park on a coordinate plane.
The table contains points along the perimeter of the park. Since the event planner wants to put a podium at one of the foci, the point where the podium could be located relative to the center will be 288 feet west.
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Answer:
Step-by-step explanation:
The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...
m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator
m2 = tan(arctan(-1/3) -45°) = -2
Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.
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We can use the point-slope form of the equation for a line to write the desired equations:
y = m(x -h) +k . . . . . line with slope m through point (h, k)
<u>Line 1</u>:
y = 1/2(x -2) +3
y = 1/2x +2
<u>Line 2</u>:
y = -2(x -2) +3
y = -2x +7
Answer: 25
Step-by-step explanation: -5 x 25 + 13 = -112
X axis : -t1 cos 60 + t2 cos 60 = 0
t2 cos 60 = t1 cos 60 ; t2 = t1
Y axis : t1 sin 60 + t2 sin 60 - 150 = 0
since t2 = t1
2t1 sin 60 = 150
t1 ( sqrt(3)/2) = 150/2
t1 = 50 [sqrt(3)]
t2 = 50 [sqrt(3)]
t3 = 150 N
hope this helps
Answer:
x=mc2 + 86
Step-by-step explanation: