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zepelin [54]
3 years ago
6

The difference of twelve times a number and nine times the number

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

3 times a number (3x)

Step-by-step explanation: replace the phrase 'a number' with the variable X. then you simply end up with 12x-9x, which equals 3x.

You might be interested in
Question 2 A birthday cake in the shape of the right-circular cylinder of radius 15cm and thickness 10cm is cut into smaller pie
finlep [7]

The volume of a piece of the cake will be 588.75 cm³.

The complete question is attached below.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

A birthday cake in the shape of the right-circular cylinder of radius 15 cm and thickness 10 cm is cut into smaller pieces.

One of the piece is shown.

Then the volume of piece of the cake will be

V = (30 / 360) x π x 15² × 10

V = 588.75 cm³

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

5 0
2 years ago
Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dis
Ronch [10]
<h2><u>Complete Question: </u></h2>

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dissimilar.

1. \frac{2}{3} $ and $ \frac{1}{3}

2. \frac{3}{4} $ and $ \frac{1}4}

3. \frac{4}{7} $ and $ \frac{7}{8}

4. \frac{2}{5} $ and $ \frac{5}{11}

5. \frac{7}{13} $ and $ \frac{7}{9}

<h2><em><u>The answers:</u></em></h2>

1. \frac{2}{3} $ and $ \frac{1}{3} - Similar (S)

2. \frac{3}{4} $ and $ \frac{1}4} - Similar (S)

3. \frac{4}{7} $ and $ \frac{7}{8} - Dissimilar (D)

4. \frac{2}{5} $ and $ \frac{5}{11} - Dissimilar (D)

5. \frac{7}{13} $ and $ \frac{7}{9} - Dissimilar (D)

Note:

  • Similar fractions have the same denominator. i.e. the bottom value of both fractions are the same.
  • Dissimilar fractions have different value as denominator, i.e. the bottom value of both fractions are not the same.

Thus:

1. \frac{2}{3} $ and $ \frac{1}{3} - They have equal denominator. <u><em>Both fractions are similar (S).</em></u>

2. \frac{3}{4} $ and $ \frac{1}4} - They have equal denominator. <em><u>Both fractions are similar (S).</u></em>

3. \frac{4}{7} $ and $ \frac{7}{8} - They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>

4. \frac{2}{5} $ and $ \frac{5}{11} - They have equal denominator. <u><em>Both fractions are dissimilar (D).</em></u>

5. \frac{7}{13} $ and $ \frac{7}{9} - They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>

Therefore, the fractions in <em><u>1 and 2 are similar (S)</u></em> while those in <em><u>3, 4, and 5 are dissimilar (D).</u></em>

<em><u></u></em>

Learn more here:

brainly.com/question/22099172

7 0
3 years ago
write an expression with (-1) as its base that will produce a positive product, and explain why your answer is valid.
Simora [160]
........................................... i dont know, i dont remember doing this
3 0
3 years ago
Read 2 more answers
2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.
likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

y = ^+_- \sqrt{-x^2+4x+4} -5

Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

\frac{52 ^+_-\sqrt{1664}}{26}

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0
3 years ago
When results from a scholastic assessment test are sent to test-takers, the percentiles associated with their scores are also gi
hram777 [196]

Answer:

The correct option is (D).

Step-by-step explanation:

Percentiles are statistical measures that are used to interpret data. It represents the data value which is more that a specific percentage of the data set.

The <em>n</em>th percentile of a data set is the value that is more that <em>n</em>% of the data set.

⇒ It is provided that a test-taker's score was at the 94th percentile for their verbal grade.

This statement implies that the test taker scored a mark more than 94% of the other test-takers, i.e. he\she performed better than 94% of the other test-takers in the verbal grade.

⇒ Also the test-taker's score was at the 16th percentile for their quantitative grade.

This implies that the test taker scored a mark more than 16% of the other test-takers, i.e. he\she performed better than 16% of the other test-takers in the quantitative grade.

Thus, the correct option is (D).

8 0
4 years ago
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