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tekilochka [14]
3 years ago
12

Find the area of both of these trapeziods using the formula (b1 + b2) • h ÷ 2.

Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer: 24 and 104

Step-by-step explanation:

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4) 3 + 2x - 8x = -15
Bond [772]

Answer:

=3

Step-by-step explanation:

Combine like terms 3-6x=-15

Subtract 3 from both sides of the equation -6x=-18

divide both sides by 6  x=3

8 0
3 years ago
What is the equation with a slope of 0 that has a point of (6,-11)?
lianna [129]

\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-11})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-11)}=\stackrel{m}{0}(x-\stackrel{x_1}{6}) \\\\\\ y+11=0\implies y=-11

5 0
3 years ago
A worker is taking boxes of nails on an elevator, each box weighs 54lb. The weight of the worker is 170lb. Write an inequality d
Tanya [424]

Answer: y=54(lb)x+170(lb)

Step-by-step explanation: that's the function for it but I tried. You need to include how much weight the elevator can hold though

6 0
3 years ago
Step by step please and thank you.
cupoosta [38]

Answer:

  the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

  p(dime first) = 4/10 = 2/5

Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

The joint probability of these two events occurring sequentially is the product of their probabilities:

  p(dime then nickel) = (2/5)×(5/9) = 2/9

_____

<em>Alternate solution</em>

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

  p(dime/nickel) = 20/90 = 2/9

8 0
3 years ago
Help Asap I am stuck
MAXImum [283]

Answer:

bro pls someone hurry i need help

Step-by-step explanation:

5 0
2 years ago
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