Answer:
LCM of 6 and 15 by Listing Multiples
Step 2: The common multiples from the multiples of 6 and 15 are 30, 60, . . . Step 3: The smallest common multiple of 6 and 15 is 30.
Given:
8 tiles
radius from the center of the archway to the inner edge of the tile. 7 ft.
radius from the center of the archway to the outer edge of the tile. 8 ft = 7 ft + 1 ft.
Area of a semi circle = π r² / 2
A = (3.14 * (7ft)²) / 2 = (3.14 * 49ft²) / 2 = 153.86 ft² / 2 = 76.93 ft²
A = (3.14 * (8ft)²) / 2 = (3.14 * 64ft²) / 2 = 200.96 ft² / 2 = 100.48 ft²
100.48 ft² - 76.93 ft² = 23.55 ft²
23.55 ft² / 8 tiles = 2.94 ft² per tile.
The answer is C 41 because those two numbers are in the middle when arranging them
For the answer to the question above, I'll provide a solution to my answer below
sin²θ + cos²θ = 1
<span>so, cos²θ = 1 - (5/6)² => 11/36 </span>
<span>=> cosθ = ±√11/6 </span>
<span>Also, tanθ = sinθ/cosθ => (5/6)/(±√11/6) </span>
<span>i.e. tanθ = ±5/√11
</span>I hope my answer helped you. Feel free to ask more questions. Have a nice day!
