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baherus [9]
3 years ago
12

PLS HELP

Mathematics
1 answer:
joja [24]3 years ago
5 0

Answer:

We would need pictures of the figures first :(

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Please help! The radius of a sphere is claimed to be 3.0 inches, correct to within 0.01 inch. Use linear approximation to estima
Vilka [71]

Answer:

0,36π inches³ or simply 1.13 inches³

Step-by-step explanation:

In this case, first, we need to calculate the volume of the sphere with the formula:

V = 4πr³/3

Replacing the data we have:

V = 4π(3)³/3

V = 36 in³

Now that we have the volume we need to calculate the resulting error. In this case, using linear approximation we have to use the derivates of V and r, so we have the following:

If V = 4πr³/3

Then the derivate of V (dV) would be:

dV = 4π*3*r²/3 dr

Where dr is the error of radius so:

dV = 4π*r² dr

Solving for dV:

dV = 4*3.14*(3)²*(0.01)

dV = 1.13 in³

So at the end, we just report the volume of the sphere as

V = 36 ± 1 in³

dV =

3 0
3 years ago
(06.01)
MAVERICK [17]

After solving I have come up with 6 2/9 or 6.22222.

4 0
3 years ago
What two numbers can you multiply to get -28 and add to get -12
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-14,2
Because if you multiply -14*2 you get -28 and if you add -14+2 you get -12. Hope this helps
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URGENT What is the angle of rotation for the following figure?
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answer is I am expecting that option d is correct answer

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