Question

Determine the area of a rectangle whose diagonal is 24cm and the angle between the diagonal is 60deg.

Answer 1

Consider, ΔBCD, in rectangle,

cos 60 = b/24

1/2 = b/24

b = 12

Now, Sin 60 = p/24

√3/2 = p/24

p = 24√3/2 = 12√3

Area would be : Length * Width = 12 * 12√3 = 144√3 cm²