The actual speed of the plane with the wind:
v² = ( 150 + 50 · cos 45°)² + ( 50 · sin 45°)²
v² = ( 150 + 35.355 )² + 35.355²
v² = 34,356.467 + 1,249.976
v = √35,606.452
v = 188.7 mph
Answer:
390 to the second power is 152100
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
For option A:
In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:
![= \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \ \ \\\\](https://tex.z-dn.net/?f=%3D%20%5Cbegin%7Bpmatrix%7D%208%5C%5Ck-2%5Cend%7Bpmatrix%7D%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7Bk-2%7D%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B10-k%7D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%5C%5C%5C)
For option B:
![P(X=k | X \geq 2 ) = \sum^{10}_{i=2} \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}](https://tex.z-dn.net/?f=P%28X%3Dk%20%7C%20X%20%5Cgeq%202%20%29%20%3D%20%20%5Csum%5E%7B10%7D_%7Bi%3D2%7D%20%20%5Cbegin%7Bpmatrix%7D%2010-i%5C%5C%20k-i%5Cend%7Bpmatrix%7D%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7Bk-i%7D%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B10-k%7D)
![k= 2,3, 4.........10](https://tex.z-dn.net/?f=k%3D%202%2C3%2C%204.........10)
Answer:
I will just give you the way of solving it
Step-by-step explanation:
First you have to change the sgape of the equation and it will become like this :
-6y=-2x+12
And then:
Y=0.33x+2
And then you have to give values to x and find y
For example i will make x zero (0)
It will become
Y=0.33(0)+12
=+12
And the points are (0,+12)
Go on like this and draw the line
Good luck
Sorry for bad english
Answer:
Are the 1 and 7 rogether? because if so then -20, -2, 4, 16, 17, if not then -20, -2, 1, 4, 7, 16