I agree with you. I added the mixed numbers and got 4 1/10 and that’s not an option.
<u>Given</u><u> info</u><u>:</u><u>-</u> Find the remainder when x^5 - 3x^3 + x - 5 is divided by x - 2
<u>Solution:</u><u>-</u>
Given,
p(x) = x^5 - 3x^3 + x - 5 , g(x) = x - 2
Let g(x) = x-2 will be the factor of p(x) if p(2) = 0.
Now, p(x) = x^5 - 3x^3 + x - 5
p(2) = (2)^5 - 3(2)^3 + 2 - 5
= (2*2*2*2*2) - 3(2*2*2) + 3 - 5
= 32 - 3(8) + 3 - 5
= 32 - 24 + 3 - 5
= 31 - 24 - 2
= 31 - 26
= 5 Remainder.
Hence, when x^5 - 3x^3 + x - 5 is divided by x - 2 , we get the remainder as 5.
A.the measures of the angles must be equal
Vertical Angles- are the angles opposite of each other when two lines cross. They are always equal.
Answer:
-3
Step-by-step explanation: or if it -11/3 - 12/3 then its -23/3
